electric field hockey answers
int: \[ E_1 = k \frac{|q_1|}{r^2} = 8.988 \times 10^9 \times \frac{3 \times 10^{-6}}{(2)^2} = 8.988 \times 10^9 \times \frac{3 \times 10^{-6}}{4} \] \[ E_1 \approx 6.74 \times 10^{3} \, \text{N/C} \] Similarly for \(q_2\):