circular raft foundation design example
ext{m}^2 \] Since the foundation is circular: \[ A = \pi r^2 \Rightarrow r = \sqrt{\frac{A}{\pi}} \approx \sqrt{\frac{66.67}{3.1416}} \approx 4.61\, \text{m} \] Therefore, the diameter (D): \[ D = 2r \approx 9.22\,