edexcel june 2013 c2 paper model answers
+ 3 = (x - 1)(x - 3) = 0 \] Solutions: \[ x=1 \quad \text{or} \quad x=3 \] Alternative method: Use quadratic formula: \[ x = \frac{4 \pm \sqrt{(-4)^2 - 4 \times 1 \times 3}}{2} = \frac{4 \pm \sqrt{16 - 12}}{2} = \frac{4 \pm 2}{2} \] which yields \(x=1\) or \(